PHP如何查找自日期时间起经过的时间?[重复]

2020/10/11 09:21 · php ·  · 0评论

如何查找自日期时间戳之类的开始经过的时间2010-04-28 17:25:43,最终输出文本应类似于xx Minutes Ago/xx Days Ago

大多数答案似乎都集中在将日期从字符串转换为时间上。看来您似乎主要是考虑将日期设为“ 5天前”格式,等等。

这就是我要这样做的方式:

$time = strtotime('2010-04-28 17:25:43');

echo 'event happened '.humanTiming($time).' ago';

function humanTiming ($time)
{

    $time = time() - $time; // to get the time since that moment
    $time = ($time<1)? 1 : $time;
    $tokens = array (
        31536000 => 'year',
        2592000 => 'month',
        604800 => 'week',
        86400 => 'day',
        3600 => 'hour',
        60 => 'minute',
        1 => 'second'
    );

    foreach ($tokens as $unit => $text) {
        if ($time < $unit) continue;
        $numberOfUnits = floor($time / $unit);
        return $numberOfUnits.' '.$text.(($numberOfUnits>1)?'s':'');
    }

}

我还没有测试过,但是应该可以。

结果看起来像

event happened 4 days ago

要么

event happened 1 minute ago

干杯

想要共享php函数,从而产生语法上正确的Facebook,如人类可读的时间格式。

例:

echo get_time_ago(strtotime('now'));

结果:

不到1分钟前

function get_time_ago($time_stamp)
{
    $time_difference = strtotime('now') - $time_stamp;

    if ($time_difference >= 60 * 60 * 24 * 365.242199)
    {
        /*
         * 60 seconds/minute * 60 minutes/hour * 24 hours/day * 365.242199 days/year
         * This means that the time difference is 1 year or more
         */
        return get_time_ago_string($time_stamp, 60 * 60 * 24 * 365.242199, 'year');
    }
    elseif ($time_difference >= 60 * 60 * 24 * 30.4368499)
    {
        /*
         * 60 seconds/minute * 60 minutes/hour * 24 hours/day * 30.4368499 days/month
         * This means that the time difference is 1 month or more
         */
        return get_time_ago_string($time_stamp, 60 * 60 * 24 * 30.4368499, 'month');
    }
    elseif ($time_difference >= 60 * 60 * 24 * 7)
    {
        /*
         * 60 seconds/minute * 60 minutes/hour * 24 hours/day * 7 days/week
         * This means that the time difference is 1 week or more
         */
        return get_time_ago_string($time_stamp, 60 * 60 * 24 * 7, 'week');
    }
    elseif ($time_difference >= 60 * 60 * 24)
    {
        /*
         * 60 seconds/minute * 60 minutes/hour * 24 hours/day
         * This means that the time difference is 1 day or more
         */
        return get_time_ago_string($time_stamp, 60 * 60 * 24, 'day');
    }
    elseif ($time_difference >= 60 * 60)
    {
        /*
         * 60 seconds/minute * 60 minutes/hour
         * This means that the time difference is 1 hour or more
         */
        return get_time_ago_string($time_stamp, 60 * 60, 'hour');
    }
    else
    {
        /*
         * 60 seconds/minute
         * This means that the time difference is a matter of minutes
         */
        return get_time_ago_string($time_stamp, 60, 'minute');
    }
}

function get_time_ago_string($time_stamp, $divisor, $time_unit)
{
    $time_difference = strtotime("now") - $time_stamp;
    $time_units      = floor($time_difference / $divisor);

    settype($time_units, 'string');

    if ($time_units === '0')
    {
        return 'less than 1 ' . $time_unit . ' ago';
    }
    elseif ($time_units === '1')
    {
        return '1 ' . $time_unit . ' ago';
    }
    else
    {
        /*
         * More than "1" $time_unit. This is the "plural" message.
         */
        // TODO: This pluralizes the time unit, which is done by adding "s" at the end; this will not work for i18n!
        return $time_units . ' ' . $time_unit . 's ago';
    }
}

我认为我有一个功能应该执行您想要的操作:

function time2string($timeline) {
    $periods = array('day' => 86400, 'hour' => 3600, 'minute' => 60, 'second' => 1);

    foreach($periods AS $name => $seconds){
        $num = floor($timeline / $seconds);
        $timeline -= ($num * $seconds);
        $ret .= $num.' '.$name.(($num > 1) ? 's' : '').' ';
    }

    return trim($ret);
}

只需将它应用到之间的差异time(),并strtotime('2010-04-28 17:25:43')为这样:

print time2string(time()-strtotime('2010-04-28 17:25:43')).' ago';

如果使用php Datetime类,则可以使用:

function time_ago(Datetime $date) {
  $time_ago = '';

  $diff = $date->diff(new Datetime('now'));


  if (($t = $diff->format("%m")) > 0)
    $time_ago = $t . ' months';
  else if (($t = $diff->format("%d")) > 0)
    $time_ago = $t . ' days';
  else if (($t = $diff->format("%H")) > 0)
    $time_ago = $t . ' hours';
  else
    $time_ago = 'minutes';

  return $time_ago . ' ago (' . $date->format('M j, Y') . ')';
}

请注意,大多数数学计算示例都具有严格的2038-01-18日期限制,并且不适用于虚构的日期。

由于存在缺乏DateTimeDateInterval基础的例子,我想提供一个多用途的功能满足了OP的需要和其他人想复合经过时期,如1 month 2 days ago以及其他一系列用例,例如显示日期而不是经过时间的限制,或过滤掉经过时间结果的一部分。

此外,大多数示例都假定经过时间是从当前时间开始的,以下功能允许该时间被期望的结束日期覆盖。

/**
 * multi-purpose function to calculate the time elapsed between $start and optional $end
 * @param string|null $start the date string to start calculation
 * @param string|null $end the date string to end calculation
 * @param string $suffix the suffix string to include in the calculated string
 * @param string $format the format of the resulting date if limit is reached or no periods were found
 * @param string $separator the separator between periods to use when filter is not true
 * @param null|string $limit date string to stop calculations on and display the date if reached - ex: 1 month
 * @param bool|array $filter false to display all periods, true to display first period matching the minimum, or array of periods to display ['year', 'month']
 * @param int $minimum the minimum value needed to include a period
 * @return string
 */
function elapsedTimeString($start, $end = null, $limit = null, $filter = true, $suffix = 'ago', $format = 'Y-m-d', $separator = ' ', $minimum = 1)
{
    $dates = (object) array(
        'start' => new DateTime($start ? : 'now'),
        'end' => new DateTime($end ? : 'now'),
        'intervals' => array('y' => 'year', 'm' => 'month', 'd' => 'day', 'h' => 'hour', 'i' => 'minute', 's' => 'second'),
        'periods' => array()
    );
    $elapsed = (object) array(
        'interval' => $dates->start->diff($dates->end),
        'unknown' => 'unknown'
    );
    if ($elapsed->interval->invert === 1) {
        return trim('0 seconds ' . $suffix);
    }
    if (false === empty($limit)) {
        $dates->limit = new DateTime($limit);
        if (date_create()->add($elapsed->interval) > $dates->limit) {
            return $dates->start->format($format) ? : $elapsed->unknown;
        }
    }
    if (true === is_array($filter)) {
        $dates->intervals = array_intersect($dates->intervals, $filter);
        $filter = false;
    }
    foreach ($dates->intervals as $period => $name) {
        $value = $elapsed->interval->$period;
        if ($value >= $minimum) {
            $dates->periods[] = vsprintf('%1$s %2$s%3$s', array($value, $name, ($value !== 1 ? 's' : '')));
            if (true === $filter) {
                break;
            }
        }
    }
    if (false === empty($dates->periods)) {
        return trim(vsprintf('%1$s %2$s', array(implode($separator, $dates->periods), $suffix)));
    }

    return $dates->start->format($format) ? : $elapsed->unknown;
}

需要注意的一件事-所提供的过滤器值的检索间隔不会延续到下一个周期。过滤器仅显示提供的周期的结果值,而不重新计算周期以仅显示所需的过滤器总数。


用法

对于OP需要显示最高期限的需求(截至2015年2月24日)。

echo elapsedTimeString('2010-04-26');
/** 4 years ago */

要显示复合期间并提供自定义的结束日期(请注意缺少提供的时间和虚构的日期)

echo elapsedTimeString('1920-01-01', '2500-02-24', null, false);
/** 580 years 1 month 23 days ago */

显示过滤周期的结果(数组的顺序无关紧要)

echo elapsedTimeString('2010-05-26', '2012-02-24', null, ['month', 'year']);
/** 1 year 8 months ago */

如果达到限制,以提供的格式(默认Ymd)显示开始日期。

echo elapsedTimeString('2010-05-26', '2012-02-24', '1 year');
/** 2010-05-26 */

还有许多其他用例。它也可以很容易地调整为接受unix时间戳和/或DateInterval对象作为开始,结束或限制参数。

为了改善@arnorhs的答案,我添加了获得更精确结果的功能,因此,例如,如果您希望自用户加入以来需要数年,数月,数天和数小时。

我添加了一个新参数,使您可以指定希望返回的精度点数。

function get_friendly_time_ago($distant_timestamp, $max_units = 3) {
    $i = 0;
    $time = time() - $distant_timestamp; // to get the time since that moment
    $tokens = [
        31536000 => 'year',
        2592000 => 'month',
        604800 => 'week',
        86400 => 'day',
        3600 => 'hour',
        60 => 'minute',
        1 => 'second'
    ];

    $responses = [];
    while ($i < $max_units && $time > 0) {
        foreach ($tokens as $unit => $text) {
            if ($time < $unit) {
                continue;
            }
            $i++;
            $numberOfUnits = floor($time / $unit);

            $responses[] = $numberOfUnits . ' ' . $text . (($numberOfUnits > 1) ? 's' : '');
            $time -= ($unit * $numberOfUnits);
            break;
        }
    }

    if (!empty($responses)) {
        return implode(', ', $responses) . ' ago';
    }

    return 'Just now';
}

我喜欢Mithun的代码,但我对其进行了一些调整,以使其给出更合理的答案。

function getTimeSince($eventTime)
{
    $totaldelay = time() - strtotime($eventTime);
    if($totaldelay <= 0)
    {
        return '';
    }
    else
    {
        $first = '';
        $marker = 0;
        if($years=floor($totaldelay/31536000))
        {
            $totaldelay = $totaldelay % 31536000;
            $plural = '';
            if ($years > 1) $plural='s';
            $interval = $years." year".$plural;
            $timesince = $timesince.$first.$interval;
            if ($marker) return $timesince;
            $marker = 1;
            $first = ", ";
        }
        if($months=floor($totaldelay/2628000))
        {
            $totaldelay = $totaldelay % 2628000;
            $plural = '';
            if ($months > 1) $plural='s';
            $interval = $months." month".$plural;
            $timesince = $timesince.$first.$interval;
            if ($marker) return $timesince;
            $marker = 1;
            $first = ", ";
        }
        if($days=floor($totaldelay/86400))
        {
            $totaldelay = $totaldelay % 86400;
            $plural = '';
            if ($days > 1) $plural='s';
            $interval = $days." day".$plural;
            $timesince = $timesince.$first.$interval;
            if ($marker) return $timesince;
            $marker = 1;
            $first = ", ";
        }
        if ($marker) return $timesince;
        if($hours=floor($totaldelay/3600))
        {
            $totaldelay = $totaldelay % 3600;
            $plural = '';
            if ($hours > 1) $plural='s';
            $interval = $hours." hour".$plural;
            $timesince = $timesince.$first.$interval;
            if ($marker) return $timesince;
            $marker = 1;
            $first = ", ";

        }
        if($minutes=floor($totaldelay/60))
        {
            $totaldelay = $totaldelay % 60;
            $plural = '';
            if ($minutes > 1) $plural='s';
            $interval = $minutes." minute".$plural;
            $timesince = $timesince.$first.$interval;
            if ($marker) return $timesince;
            $first = ", ";
        }
        if($seconds=floor($totaldelay/1))
        {
            $totaldelay = $totaldelay % 1;
            $plural = '';
            if ($seconds > 1) $plural='s';
            $interval = $seconds." second".$plural;
            $timesince = $timesince.$first.$interval;
        }        
        return $timesince;

    }
}

将[saved_date]转换为时间戳。获取当前时间戳。

当前时间戳-[保存日期]时间戳。

然后可以使用date()格式化它;

通常,您可以使用strtotime()函数将大多数日期格式转换为时间戳。

适用于任何版本的PHP的一个选项是执行已建议的操作,如下所示:

$eventTime = '2010-04-28 17:25:43';
$age = time() - strtotime($eventTime);

那会给你几秒钟的年龄。从那里,您可以根据需要显示它。

但是,这种方法的一个问题是,它不会考虑DST造成的时移。如果这不是一个问题,那就去吧。否则,您可能需要在DateTime类中使用diff()方法不幸的是,仅当您至少使用PHP 5.3时,这才是一个选择。

使用这个,你可以得到

    $previousDate = '2013-7-26 17:01:10';
    $startdate = new DateTime($previousDate);
    $endDate   = new DateTime('now');
    $interval  = $endDate->diff($startdate);
    echo$interval->format('%y years, %m months, %d days');

请参阅此
http://ca2.php.net/manual/en/dateinterval.format.php

尝试以下回购之一:

https://github.com/salavert/time-ago-in-words

https://github.com/jimmiw/php-time-ago

我刚开始使用后者,就可以解决问题,但是当所讨论的日期距离太远时,也就没有确切日期的stackoverflow风格回退,也不支持将来的日期-API有点时髦,但至少似乎完美无缺地工作并得到维护...

为了找出经过的时间,我通常使用time()而不是date()格式化的时间戳。然后获取后一个值与前一个值之间的差,并相应地设置格式。 time()不能替代,date()但在计算经过时间时完全有帮助。

例:

time()看起来像这样的值1274467343每秒增加一次。因此,您可以拥有$erlierTimevalue1274467343$latterTimevalue 1274467500,然后做$latterTime - $erlierTime以秒为单位的时间流逝。

自己写

function getElapsedTime($eventTime)
{
    $totaldelay = time() - strtotime($eventTime);
    if($totaldelay <= 0)
    {
        return '';
    }
    else
    {
        if($days=floor($totaldelay/86400))
        {
            $totaldelay = $totaldelay % 86400;
            return $days.' days ago.';
        }
        if($hours=floor($totaldelay/3600))
        {
            $totaldelay = $totaldelay % 3600;
            return $hours.' hours ago.';
        }
        if($minutes=floor($totaldelay/60))
        {
            $totaldelay = $totaldelay % 60;
            return $minutes.' minutes ago.';
        }
        if($seconds=floor($totaldelay/1))
        {
            $totaldelay = $totaldelay % 1;
            return $seconds.' seconds ago.';
        }
    }
}

在这里,我使用自定义函数来查找自日期时间以来经过的时间。


回声Datetodays('2013-7-26 17:01:10');

函数Datetodays($ d){

        $ date_start = $ d;
        $ date_end = date('Ymd H:i:s');

        define('SECOND',1);
        define('MINUTE',SECOND * 60);
        define('HOUR',MINUTE * 60);
        define('DAY',HOUR * 24);
        define('WEEK',DAY * 7);

        $ t1 = strtotime($ date_start);
        $ t2 = strtotime($ date_end);
        如果($ t1> $ t2){
            $ diffrence = $ t1-$ t2;
        }其他{
            $ diffrence = $ t2-$ t1;
        }

        // echo“ 
”。$ date_end。“”。$ date_start。“”。$ diffrence; $ results ['major'] = array(); //整数表示日期时间关系中的较大数字 $ results1 = array(); $ string =''; $ results ['major'] ['weeks'] =下限($ diffrence / WEEK); $ results ['major'] ['days'] =下限($ diffrence / DAY); $ results ['major'] ['hours'] =楼层($ diffrence / HOUR); $ results ['major'] ['minutes'] = floor($ diffrence / MINUTE); $ results ['major'] ['seconds'] = floor($ diffrence / SECOND); // print_r($ results); //逻辑: //步骤1:获取主要结果并将其转换为原始秒数(它将减去差值的秒数) //例如:$ result =($ results ['major'] ['weeks'] * WEEK) //步骤2:从差(总时间)中减去较小的数字(结果) //例如:$ minor_result = $ difference-$ result //步骤3:将生成的时间以秒为单位,并将其转换为次格式 //例如:floor($ minor_result / DAY) $ results1 ['weeks'] =下限($ diffrence / WEEK); $ results1 ['days'] = floor(((($ diffrence-($ results ['major'] ['weeks'] * WEEK))/ DAY)); $ results1 ['hours'] = floor(((($ diffrence-($ results ['major'] ['days'] * DAY))/ HOUR))); $ results1 ['minutes'] = floor(((($ diffrence-($ results ['major'] ['hours'] * HOUR))/ MINUTE)); $ results1 ['seconds'] = floor(((($ diffrence-($ results ['major'] ['minutes'] * MINUTE))/ SECOND))); // print_r($ results1); if($ results1 ['weeks']!= 0 && $ results1 ['days'] == 0){ 如果($ results1 ['weeks'] == 1){ $ string = $ results1 ['weeks']。' 一周前'; }其他{ 如果($ results1 ['weeks'] == 2){ $ string = $ results1 ['weeks']。' 几周前'; }其他{ $ string ='2周前'; } } } elseif($ results1 ['weeks']!= 0 && $ results1 ['days']!= 0){ 如果($ results1 ['weeks'] == 1){ $ string = $ results1 ['weeks']。' 一周前'; }其他{ 如果($ results1 ['weeks'] == 2){ $ string = $ results1 ['weeks']。' 几周前'; }其他{ $ string ='2周前'; } } } elseif($ results1 ['weeks'] == 0 && $ results1 ['days']!= 0){ 如果($ results1 ['days'] == 1){ $ string = $ results1 ['days']。“一天前”; }其他{ $ string = $ results1 ['days']。' 几天前'; } } elseif($ results1 ['days']!= 0 && $ results1 ['hours']!= 0){ $ string = $ results1 ['days']。'天和'。$ results1 ['hours']。“小时前”; } elseif($ results1 ['days'] == 0 && $ results1 ['hours']!= 0){ 如果($ results1 ['hours'] == 1){ $ string = $ results1 ['hours']。' 一个小时前'; }其他{ $ string = $ results1 ['hours']。“小时前”; } } elseif($ results1 ['hours']!= 0 && $ results1 ['minutes']!= 0){ $ string = $ results1 ['hours']。'小时和'。$ results1 ['minutes']。' 几分钟前'; } elseif($ results1 ['hours'] == 0 && $ results1 ['minutes']!= 0){ if($ results1 ['minutes'] == 1){ $ string = $ results1 ['minutes']。'分钟前'; }其他{ $ string = $ results1 ['minutes']。' 几分钟前'; } } elseif($ results1 ['minutes']!= 0 && $ results1 ['seconds']!= 0){ $ string = $ results1 ['minutes']。分钟和'。$ results1 ['seconds']。“秒前”; } elseif($ results1 ['minutes'] == 0 && $ results1 ['seconds']!= 0){ 如果($ results1 ['seconds'] == 1){ $ string = $ results1 ['seconds']。'第二前'; }其他{ $ string = $ results1 ['seconds']。“秒前”; } } 返回$ string; } ?>

您可以直接从WordPress核心文件中获得此功能,在这里看看

http://core.trac.wordpress.org/browser/tags/3.6/wp-includes/formatting.php#L2121

function human_time_diff( $from, $to = '' ) {
    if ( empty( $to ) )
        $to = time();

    $diff = (int) abs( $to - $from );

    if ( $diff < HOUR_IN_SECONDS ) {
        $mins = round( $diff / MINUTE_IN_SECONDS );
        if ( $mins <= 1 )
            $mins = 1;
        /* translators: min=minute */
        $since = sprintf( _n( '%s min', '%s mins', $mins ), $mins );
    } elseif ( $diff < DAY_IN_SECONDS && $diff >= HOUR_IN_SECONDS ) {
        $hours = round( $diff / HOUR_IN_SECONDS );
        if ( $hours <= 1 )
            $hours = 1;
        $since = sprintf( _n( '%s hour', '%s hours', $hours ), $hours );
    } elseif ( $diff < WEEK_IN_SECONDS && $diff >= DAY_IN_SECONDS ) {
        $days = round( $diff / DAY_IN_SECONDS );
        if ( $days <= 1 )
            $days = 1;
        $since = sprintf( _n( '%s day', '%s days', $days ), $days );
    } elseif ( $diff < 30 * DAY_IN_SECONDS && $diff >= WEEK_IN_SECONDS ) {
        $weeks = round( $diff / WEEK_IN_SECONDS );
        if ( $weeks <= 1 )
            $weeks = 1;
        $since = sprintf( _n( '%s week', '%s weeks', $weeks ), $weeks );
    } elseif ( $diff < YEAR_IN_SECONDS && $diff >= 30 * DAY_IN_SECONDS ) {
        $months = round( $diff / ( 30 * DAY_IN_SECONDS ) );
        if ( $months <= 1 )
            $months = 1;
        $since = sprintf( _n( '%s month', '%s months', $months ), $months );
    } elseif ( $diff >= YEAR_IN_SECONDS ) {
        $years = round( $diff / YEAR_IN_SECONDS );
        if ( $years <= 1 )
            $years = 1;
        $since = sprintf( _n( '%s year', '%s years', $years ), $years );
    }

    return $since;
}

arnorhs对功能“ humanTiming”的改进。它将计算时间字符串到人类可读文本版本的“完全拉伸”转换。例如说“ 1周2天1小时28分钟14秒”

function humantime ($oldtime, $newtime = null, $returnarray = false)    {
    if(!$newtime) $newtime = time();
    $time = $newtime - $oldtime; // to get the time since that moment
    $tokens = array (
            31536000 => 'year',
            2592000 => 'month',
            604800 => 'week',
            86400 => 'day',
            3600 => 'hour',
            60 => 'minute',
            1 => 'second'
    );
    $htarray = array();
    foreach ($tokens as $unit => $text) {
            if ($time < $unit) continue;
            $numberOfUnits = floor($time / $unit);
            $htarray[$text] = $numberOfUnits.' '.$text.(($numberOfUnits>1)?'s':'');
            $time = $time - ( $unit * $numberOfUnits );
    }
    if($returnarray) return $htarray;
    return implode(' ', $htarray);
}

最近不得不这样做-希望这对某人有帮助。它不能满足所有可能性,但可以满足我对项目的需求。

https://github.com/duncanheron/twitter_date_format

https://github.com/duncanheron/twitter_date_format/blob/master/twitter_date_format.php

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